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tamaranim1 [39]
3 years ago
7

3(n+1)=15-n solve for n

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

Answer:

n = 3

Step-by-step explanation:

3(n+1) = 15 - n

3n + 3 = 15 - n

3n +n = 15 - 3

4n = 12

n = 3

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What ia expanded form
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<span>a way to write numbers by adding the value of its digits. 
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5 0
3 years ago
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The length of a rectangle is 5 times larger than x. The width is 4 cm less than the length. The perimeter is at least 96 cm. Wha
Ede4ka [16]

We know that the perimeter of a rectangle = 2(l + w)

l = length

w = width

In our problem,

l = 5x

w = 5x - 4

Let's create an inequality to help us solve this problem.

2(5x + (5x - 4)) ≥ 96

Let's start off by simplifying the terms inside the parentheses.

2(10x - 4) ≥ 96

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20x - 8 ≥ 96

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20x ≥ 104

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Let's plug 5.2 into x for our length and width.

Length = 5x = 5(5.2) = 26 cm

Width = 5x - 4 = 5(5.2) - 4 = 26 - 4 = 22 cm

The smallest possible dimensions for the rectangle are, length = 26 cm and width = 22 cm  

6 0
3 years ago
Read 2 more answers
From the information given determine the quadrant in which the terminal point (determined by an angle with a measure of a) lies.
Otrada [13]

Answer:

If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant IV.

Step-by-step explanation:

Sine and cosine values, relation with quadrant:

Quadrant 1: Sine > 0, cosine > 0.

Quadrant 2: Sine > 0, cosine < 0.

Quadrant 3: Sine < 0, cosine < 0.

Quadrant 4: Sine < 0, cosine > 0.

If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant

Both negative, so III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant

Sine positive, cosine negative, so II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant

Both positive, so I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant

Sine negative, cosine positive, so IV.

6 0
3 years ago
Which situation is best represented by the following equation? 40w + 12.50 = 492.50 A) Nicole paid $40 for self-defense classes.
Anastaziya [24]
Your answer would be D. 
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6 0
3 years ago
the total number of cupcakes carmen can bake depends on the amount of time she spends baking. Carmen can back 84 cupcakes in 1.6
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84 cupcakes    
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7 0
3 years ago
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