Answer: Because
, therefore
.
What so what do you do i'm not gitting it
Answer:
-975 / -65x = y
Step-by-step explanation:
hope that helps :)
Answer:
![x=-\frac{3\sqrt{2}}{2},\frac{3}{4},\frac{3\sqrt{2} }{2}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B3%5Csqrt%7B2%7D%7D%7B2%7D%2C%5Cfrac%7B3%7D%7B4%7D%2C%5Cfrac%7B3%5Csqrt%7B2%7D%20%7D%7B2%7D)
Step-by-step explanation:
Given expression is,
f(x) = 8x³ - 6x² - 36x + 27
For zeros of the function,
f(x) = 0
8x³ - 6x² - 36x + 27 = 0
2x²(4x - 3) - 9(4x - 3) = 0
(2x² - 9)(4x - 3) = 0
(2x² - 9) = 0
x² = ![\frac{9}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B2%7D)
x = ![\pm\frac{3}{\sqrt{2}}](https://tex.z-dn.net/?f=%5Cpm%5Cfrac%7B3%7D%7B%5Csqrt%7B2%7D%7D)
x = ![\pm \frac{3\sqrt{2}}{2}](https://tex.z-dn.net/?f=%5Cpm%20%5Cfrac%7B3%5Csqrt%7B2%7D%7D%7B2%7D)
Or (4x - 3) = 0
x = ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
Therefore, all zeros of the given functions are
.
f ( x ) = 1 - e^x
We have too find the slope of the graph at the point: f ` ( x o ), where x o is a coordinate of the point where the graph crosses the x-axis ). Also an equation of the tangent line is: y - y o = f ` ( x o ) ( x - x o ) , but we don`t need it here ( we just need to find the slope ).
1 - e ^x = 0
e ^x = 1 => x o = 0
f ` ( x ) = - e ^x
f` ( 0 ) = - e^0 = - 1
The slope is : m = - 1