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vazorg [7]
3 years ago
7

In the diagram provided, line I is parallel to line m. Select which of the following statements could be used to prove that

Mathematics
1 answer:
atroni [7]3 years ago
8 0
<h3>Answer: There is only one answer and it is choice B</h3><h3>Angle 1 and angle 4 are alternate interior angles</h3>

========================================================

Explanation

  • A. This is false because it should be angle 4 + angle 5 = 180 without the angle 6. Adding on angle 6 results in some angle larger than 180. Note how angle 5 = (angle 3)+(angle 6).
  • B. This is true and useful to showing that the three angles of a triangle add to 180 degrees. This is because you'll use the fact that angles 4, 5 and 6 combine to 180 degrees.
  • C. While this is a true statement by the exterior angle theorem, it is not useful to the proof. It is better to state that angle 2 and angle 6 are congruent because they are alternate interior angles.
  • D. Like choice C, it is true but not useful. It's better to say that angle 1 is congruent to angle 4. See choice B above.

Note how it's not enough for a statement to be true. It also needs to be relevant or useful to the context at hand. A more simpler example of this could be stating that x+x = 2x.

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After 6x+48=72, you have to subtract 48 on both sides not add. Your final answer will be x=4. 72-48=24.. 24/6= 4.
8 0
3 years ago
Bill Gates wrote a computer program that generates three random numbers
Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

p(AB)=p(A)\cdot p(B) (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

s=1

So, the probability of drawing a 3 in 1 draw is

p(3)=\frac{s}{n}=\frac{1}{10}

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}

7 0
3 years ago
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Answer:

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Step-by-step explanation:

40 x 15 = 600

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Answer:

5^{2}(7) = 175

Step-by-step explanation:

hope this helps! just follow the order of operations. :)

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