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2 years ago

8. Lesly took a test with 30 questions. The ratio of correct answers to incorrect answers

Mathematics

1 answer:

Firlakuza [10]2 years ago

4 0

Lesly got 14 answers correctly.

Let the correct answers be C.

Let the incorrect answers be I.

Given the following data:

Total number of questions = 30 questions.

Ratio of C to I = 7 : 8

C to I = 7 + 8 = 15

To find the number of answers she got correctly;

$C = \frac{7}{15}$ × $30$

$C = 7$ × $2$

Correct answers, C = 14 answers

Therefore, Lesly got 14 answers correctly.

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(-41) + (-40) = ?

ValentinkaMS [17]

Answer:

$( - 41) + ( - 40) \\ - 41 - 40 \\ 81$

Step-by-step explanation:

I hope I helped you! :)

4 0

2 years ago

NEED HELP ASAP WILL GIVE BRAINLIEST

Zepler [3.9K]

Answer:

Step-by-step explanation:

I used the formula. it took a long but i got it! Brainly pls!

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2 years ago

Find all angles and pls show steps

Ghella [55]

Answer:

Both angles have a measure of 134degrees, y = 27degrees.

Step-by-step explanation:

As per what is given in the problem:

There are 2 parallel lines, both are intersected by a transversal.

Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.

The is meanse that:

3y + 53 = 7y - 55

Solve using inverse operations:

3y + 53 = 7y - 55

+55 +55

3y + 108 = 7y

-3y -3y

108 = 4y

/4 /4

27 = y

Now, substitute back in to find the value of the angle:

3y + 53

y = 27

3 ( 27 ) + 53

81 + 53

= 134

Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.

7 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Please help solve the ineaquality x over 3 is < than 3

elena55 [62]

We have an inequation:
x/3 < 3
⇒ x < 3*3
⇒ x < 9

The final answer is x < 9~

7 0

3 years ago