36kg in the ratio 1:3:5
1 answer:
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Answer:
We conclude that the mean IQ of her students is different from the national average.
Step-by-step explanation:
We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.
The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113
Let, Null Hypothesis, :
= 100 {means that the mean IQ of her students is same as of national average}
Alternate Hypothesis, :
100 {means that the mean IQ of her students is different from the national average}
(a) The test statistics that will be used here is One sample z-test statistics;
T.S. = ~ N(0,1)
where, Xbar = sample mean score = 113
s = population standard deviation = 15
n = sample of students = 144
So, test statistics =
= 10.4
Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.
Therefore, we conclude that the mean IQ of her students is different from the national average.
Answer:
Each hotdog costs $1.65
Each juice drink costs $1.05
Step-by-step explanation:
Let's begin by letting represent the number of hot dogs and
the number of juice drinks.
The Baxter family bought 6 hot dogs and 4 juices for $14.10.
The Farley family bought 3 hot dogs and 4 juices for $9.15.
Now, we subtract these equations.
Since has reversed coefficients, it gets eliminated. Now solve for x.
NOW, we find y by substituting x with 1.65 (in either equation).
We'll use the first equation.
= 1.65
= 1.05
represents hotdogs and
represents juice drinks.
Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.
<em> I hope this helps! :)</em>