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2 years ago

36kg in the ratio 1:3:5

Mathematics

1 answer:

suter [353]2 years ago

6 0

the answer are 4kg ,12kg and 20 kg

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Solve the radical equation. sqrt 25 – 40x = X – 10

Citrus2011 [14]

-40x=-10-20

-40x=-35

x= 7/8

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2 years ago

Material for a dress costs £5.50 per metre. find the cost of 10cm and 70cm

Zielflug [23.3K]

Answer:

The cost of 10 cm and 70 cm are £0.55 and £3.85 respectively.

Step-by-step explanation:

Material for a dress costs £5.50 per meter.

We know that, 1 meter = 100 cm.

Suppose, the cost of 10 cm material is $x$ and the cost of 70 cm material is $y$

Now, according to the ratio of "cost" to the "length of material" , we will get.......

$\frac{x}{10} =\frac{5.50}{100}\\ \\ 100x=10*5.50=55\\ \\ x=\frac{55}{100}=0.55$

and

$\frac{y}{70} =\frac{5.50}{100}\\ \\ 100y=70*5.50=385\\ \\ x=\frac{385}{100}=3.85$

So, the cost of 10 cm material is £0.55 and the cost of 70 cm material is £3.85

5 0

2 years ago

Can someone help me find my error

AfilCa [17]

Answer:

try dividing 102 by 4 then after that make the length a lil bit bigger than the width but make sure it still equals 102

Step-by-step explanation:

mark me brainleist and ill give solution

6 0

3 years ago

Find the surface area of the composite figure. Round the answer to the nearest tenth.

Svetllana [295]

Answer:

3+4+5+11= 56

Step-by-step explanation:

3 0

3 years ago

Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples

zheka24 [161]

Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25

Step-by-step explanation:

melanin content Total

high low

moisture high 13 10 23

content low 47 30 77

Total 60 40 100

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)= $\dfrac{40}{100}=0.40$

b) Total skin samples has high moisture content = 13+10=23

P(B) = $\dfrac{23}{100}=0.23$

c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) = $\dfrac{10}{100}=0.10$

Using conditional probability formula , $P (A|B)=\dfrac{P(A\cap B)}{P(B)}$

$P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435$

d) $P (B|A)=\dfrac{P(A\cap B)}{P(A)}$

$P (B|A)=\dfrac{0.10}{0.40}=0.25$

8 0

3 years ago

36kg in the ratio 1:3:5​

36kg in the ratio 1:3:5