30+ Points!!! 5. Solve the following inequalities. a) 2 log3x – 2 logx3 -3 <0
1 answer:
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Step 1. Type it into a Google search box or calculator. (You need to use a calculator anyway.) The result is 3177 4/9.
If you're doing this according to the Order of Operations, you do the multiplication and division left to right. This means the first calculation you do is
255/6 = 42.5
Next, you multiply by 672
42.5*672 = 28560
Then divide by 9
28560/9 = 3173 3/9
You continue by doing the division
37/9 = 4 1/9
And finish by adding the two results
3173 3/9 + 4 1/9 = 3174 4/9
_____
If you're doing this by hand, you can recognize the first term as the product of two fractions, so is the product of numerators divided by the product of denominators.
(255*672)/(6*9)
Using your knowledge of divisibility rules, you can do the division 672/6 to simplify this to
(255*112)/9
Now, the first term and the second term have the same denominator, so you can add the numerators before you do the division.
(255*112 + 37)/9 = (28560 + 37)/9 = 28597/9
You end up having to do only two simple divisions, rather than 3 of them.
28597/9 = 3177 4/9
If you're doing this according to the Order of Operations, you do the multiplication and division left to right. This means the first calculation you do is
255/6 = 42.5
Next, you multiply by 672
42.5*672 = 28560
Then divide by 9
28560/9 = 3173 3/9
You continue by doing the division
37/9 = 4 1/9
And finish by adding the two results
3173 3/9 + 4 1/9 = 3174 4/9
_____
If you're doing this by hand, you can recognize the first term as the product of two fractions, so is the product of numerators divided by the product of denominators.
(255*672)/(6*9)
Using your knowledge of divisibility rules, you can do the division 672/6 to simplify this to
(255*112)/9
Now, the first term and the second term have the same denominator, so you can add the numerators before you do the division.
(255*112 + 37)/9 = (28560 + 37)/9 = 28597/9
You end up having to do only two simple divisions, rather than 3 of them.
28597/9 = 3177 4/9
"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?
well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.
well, we can check by simply getting the distance from the center to the point (4,-1).