Answer:
The value of MA in third class lever is always less than one because the load arm is greater than the effort arm.
Step-by-step explanation:
As we know that when the load arm is greater than the effort arm, the mechanical advantage will always be lesser than one, which results in gain in speed.
Answer:
Step-by-step explanation:
<em>Step 1: Define the way to calculate distance between 2 points in two-dimensional (2D) plane</em>
Supposing that there are two points and on 2D plane.
The distance between these two points is calculated by:
<em>Step 2: Calculate the distance </em> <em>between </em><em> & </em><em> and distance </em> <em>between </em><em> and </em>
Applying the formula in step 1:
<em>Step 3: Compare and conclude</em>
Because => => N is closer to P than M
Hope this helps!
:)
Answer:
12w
Step-by-step explanation:
you multiply the outside by the inside
3(4w)
3 multiply 4 then w
Given:
Universal set is all positive integers {1,2,3...}
Set A is the set of all positive <u>ODD</u> integers {1,3,5,7...}
The question asks us to find , which is the <em>complement of set A</em>. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.
It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.
ANSWER: "{x|x ∈ U and is an even positive integer}"
Given
<em>e</em> ˣʸ = sec(<em>x</em> ²)
take the derivative of both sides:
d/d<em>x</em> [<em>e</em> ˣʸ] = d/d<em>x</em> [sec(<em>x</em> ²)]
Use the chain rule:
<em>e</em> ˣʸ d/d<em>x</em> [<em>xy</em>] = sec(<em>x</em> ²) tan(<em>x</em> ²) d/d<em>x</em> [<em>x</em> ²]
Use the product rule on the left, and the power rule on the right:
<em>e</em> ˣʸ (<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em>) = sec(<em>x</em> ²) tan(<em>x</em> ²) (2<em>x</em>)
Solve for d<em>y</em>/d<em>x</em> :
<em>e</em> ˣʸ (<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em>) = 2<em>x</em> sec(<em>x</em> ²) tan(<em>x</em> ²)
<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em> = 2<em>x</em> <em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²)
<em>x</em> d<em>y</em>/d<em>x</em> = 2<em>x</em> <em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²) - <em>y</em>
d<em>y</em>/d<em>x</em> = 2<em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²) - <em>y</em>/<em>x</em>
Since <em>e</em> ˣʸ = sec(<em>x</em> ²), we simplify further to get
d<em>y</em>/d<em>x</em> = 2 tan(<em>x</em> ²) - <em>y</em>/<em>x</em>