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xxMikexx [17]
3 years ago
12

I know I made a few errors but I don’t know which ones please help me

Chemistry
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

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Lakesha gave three tenths of her cookies to Bailey and five tenths of her cookies to Helen. What fraction of her cookies did Lak
Mashutka [201]

Answer:

a . eight tenths of her cookies

Explanation:

Let the total number of Lakesha's cookies be represented by x.

So that;

She gave three tenths to Bailey = \frac{3}{10} of x

                                                     = \frac{3x}{10}

She gave five tenths to Helen = \frac{5}{10} of x

                                                  = \frac{5x}{10}

Fraction of Lakesha's cookies given away = \frac{3x}{10} + \frac{5x}{10}

                                                      = \frac{3x+ 5x}{10}

                                                      = \frac{8x}{10}

Thus, the fraction of cookies given away by Lakesha is \frac{8}{10}.

6 0
3 years ago
Suppose that Biuret reagent turns purple when it is added to an unknown substance. What can you conclude about the substance?
Oksi-84 [34.3K]

Answer:

the unknown substance is a protein

Explanation:

The biuret test is one of the tests for proteins. It  can be used to  detect peptide linkages. The biuret test is carried out in an alkaline solution. A coordination complex is formed  leading to the appearance of a  violet color.

Summarily, the biuret method is a colorimetric technique used to test for proteins and peptides.  It involves the formation of  a purple (violet) complex of Copper salts in alkaline solution.

Hence when the biuret reagent is added to an unknown substance and it turns purple, the unknown substance is a protein

6 0
3 years ago
The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe
Irina-Kira [14]

Answer:

t=147.24\ min

Explanation:

Given that:

Half life = 30 min

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30}\ min^{-1}

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration [A_0] = 7.50 mg

Final concentration [A_t] = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

0.25=7.50e^{-0.0231\times t}

750e^{-0.0231t}=25

750e^{-0.0231t}=25

x=\frac{\ln \left(30\right)}{0.0231}

t=147.24\ min

6 0
3 years ago
What is the base dissociation constant for a weak base at equilibrium, B + H2O <===> BH+ + OH–?
podryga [215]
Depends on what the base is. You would reference the base dissociation chart for that value.
3 0
3 years ago
Read 2 more answers
An average, how many eggs does a female release each<br> cycle?
bagirrra123 [75]

Answer:

At birth, there are approximately 1 million eggs; and by the time of puberty, only about 300,000 remain. Of these, only 300 to 400 will be ovulated during a woman's reproductive lifetime. Fertility can drop as a woman ages due to decreasing number and quality of the remaining eggs.

Explanation:

Hope This Helps!!

5 0
3 years ago
Read 2 more answers
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