We are given with the reaction that produces methanol from the reaction of hydrogen gas and carbon monoxide. This is expressed in the balanced equation: 2H2+CO=CH3OH. We need to identify the limiting reactant. Convert each mass to moles and divide each with their corresponding stoich. coeff. For H2, this is equal to 3 and for CO, this is equal to 2.66. Hence CO is the limiting reactant. From this, the amount of methanol produced is 85.14 grams.
Answer:
16.8%
Explanation:
31% NaOH molar mass 40 gm
69% H2O molar mass 18 gm
1000 gm would be
310 gm NaOH or 310/40 = 7.75 moles
690 gm of H2O or 690/18 = 38.333 moles
7.75 / (7.75 + 38.333) = .168 mole fraction
D.) It depends cuz no yeild is 100%..I mean side reactions also occur in most of the reactions. So mass of the reactant is not equal to the mass of the product. Hope it helps
P=nRTV
hope this help<span />
