Express the following numbers as standard form: a) 1.52 x 10^-2 b) 7.78 x 10^-8

What is the mass of cyclohexane solvent, in kg, if 9.76 mL are used and the cyclohexane has a density of 0.779 g/mL?

nordsb [41]

Answer:

0.0076kg

Explanation:

To get the mass, we use the relation among density, mass and volume.

Mass = density * volume

Here mass? , density = 0.779g/ml , volume = 9.76ml

Mass = 9.76 * 0.779 = 7.60g

Answer is wanted in kg so we divide by 1000. This is 7.60/1000 = 0.0076kg

3 0

3 years ago

Which of the following is an example of an endothermic process? (2 points) Gasoline burning in a combustion engine A chocolate b

frozen [14]

A chocolate bar melting in a hot car

8 0

2 years ago

Read 2 more answers

A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

kupik [55]

hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.

please mark me as brainliest............

follow me..........

6 0

2 years ago

Given the following reaction: \ce{Cu + 2AgNO3 -> 2Ag + Cu(NO3)2}Cu+2AgNO3 2Ag+Cu(NOX 3 )X 2 How many moles of \ce{Ag}

Alexandra [31]

Answer:

0.252 mol

Explanation:

Given the following reaction:

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 is available in excess.

First, we write the balanced equation.

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

We can establish the following relations.

The molar mass of Cu is 63.55 g/mol.
The molar ratio of Cu to Ag is 1:1.

The moles of Ag produced from 16.0 g of Cu are:

$16.0gCu.\frac{1molCu}{63.55gCu} .\frac{1molAg}{1molCu} =0.252 molAg$

6 0

3 years ago

Read 2 more answers

Many homes that are not

andrew11 [14]

Answer:

pump that is the answer hope its right

6 0

2 years ago