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2 years ago

14

Find an expression for perimeter

1 answer:

user100 [1]2 years ago

8 0

Step-by-step explanation:

Perimeter of a rectangle= 2(l+b)

= 2( 4m-1+3m+2)

=2(7m+1)

= 14m+2

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Directed line segment AB has endpoints A(2,3) and B(8,15). Point P has coordinated P(6,11). What ratio does P partition AB into?

Vladimir79 [104]

Refer to the graph shown below. It confirms that points A, B and P are
collinear.

Calculate the length of AP (as a).
a = √[(6 - 2)² + (11 - 3)²]
= 8.9443

Calculate the length of BP (as b).
b = √[(8 - 6)² + (15 - 11)²]
= 4.4721

Calculate ratio a/b.
a/b = 8.9443/4.4721 = 2
Therefore P partitions AB in a 2:1 ratio so that AP = 2*BP.

Answer: 2:1 ratio.

7 0

3 years ago

Express the following rational number as decimals 615/125

GarryVolchara [31]

Answer:

4.92

Step-by-step explanation:

615 divided by 125 equals to 4.92

4 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

The price of an electronic puzzle was reduced be $7

Nimfa-mama [501]

Answer:

Step-by-step explanation:

total price was reduced by $ 7

let x = the total price........ x - 7

he bought 10.....and it cost him $ 130

10(x - 7) = 130

10x - 70 = 130

10x = 130 + 70

10x = 200

x = 200/10

x = 20 <====== original price

7 0

3 years ago

NEED HELP ASAP WILL GIVE BRAINLYEST

Stolb23 [73]

Answer:

it is the first answer

Step-by-step explanation:

5 0

3 years ago

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