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musickatia [10]
2 years ago
15

8fsquare + 4f - 60 its an math equation can anyone plz gimme the answer

Mathematics
1 answer:
hammer [34]2 years ago
6 0

Answer:

f = -3 , 5/2

Step-by-step explanation:

8f² + 4f - 60 = 0

Divide the entire equation by 4

2f² + f  - 15 = 0

Product = -30

Sum = 1

Factors = -5 , 6      {(-5)*6 = -30  and -5 +6 = 1}

2f² + f -15 = 0        {Rewrite the middle term using the factors}

2f² + 6f - 5f -15 = 0

2f(f + 3) - 5(f + 3) = 0

(f +3) (2f - 5) = 0

f +3  = 0    ; 2f -5 = 0

f = -3         ; 2f = 5

                    f = 5/2

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Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
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x = -1/-1/5
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Now it contains the points (1,2)
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2 years ago
Perpendicular to the line y=1/2x-8; passes through (7,-6). Write the slope-intercept form of the equation.
Airida [17]

<u>ANSWER: </u>

The slope intercept form of the required line is y = -2x + 20.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{1}{2} x-8$

And, Perpendicular line to the given line  passes through (7,-6).  

We need to find the slope intercept form of perpendicular line of given line.  

We already have the point (7, -6) but we need to find the slope.

Now, we know that, product of slopes of two perpendicular lines equals to -1.

Slope of given line is \frac{1}{2}, by comparing with the general form of slope intercept form.

\frac{1}{2} \times slope of required line = -1

Slope of perpendicular line = -2

Now, line equation of perpendicular line in point slope form is

$y-y_{1}=m\left(x-x_{1}\right)$

y – (-6) = -2(x – 7)

y + 6 = -2x + 14

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the above equation is in the form of slope intercept form of a line equation  

where slope m = -2 and intercept c = 20

hence, the slope intercept form of the required line is y = -2x + 20.

6 0
3 years ago
How many different right triangles are there with a hypotenuse of lenght 5 cm
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Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

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There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

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3 years ago
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<u>Please mark this answer as the Brainliest if it helped! Thank you.</u>

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