P,Q,R can't be 0, because their product is nonzero. Either of S and T could be 0, but the third one only works if S is 0.
FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7
y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7
HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5
no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.
Step-by-step explanation:
that's for Part B
Part C: triangles PQR and P"Q"R" are not congruent since the corresponding sides are not equal
if PLAN A is cheaper than PLAN B then,
P (A) < P (B)
30+0.01t < 20+0.05t (subtract 0.05t from both sides)
29.95-0.04t < 19.95 (subtract 29.95 from both sides)
-0.04t < -10 (divide both sides by -0.04)
t > 250
So plan A is cheaper than plan B when you send more than 250 texts.
Hope it helps.
Answer: 9/17
Reason
The reciprocal is simply flipping the denominator and numerator of a fraction.
1-8/9 as a mixed fraction is 17/9
So the reciprocal would be to flip it,
Giving you 9/17 which is in its simplest form
