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Juli2301 [7.4K]
3 years ago
7

MOVIES Employees at a local movie theater work overlapping 8-hour shifts from noon to 8 P.M. or from 4 P.M. to midnight. The tab

le below shows the number of employees needed and their corresponding pay. Find the numbers of day-shift workers and night shift workers that should be scheduled to minimize the cost. What is the minimal cost?​
Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

8 day shift and 6 night shift. minimal cost is $776

Step-by-step explanation:

anygoal [31]3 years ago
8 0

In linear programming the constraints and the objective function are composed of linear decision variables

The schedule that minimize the cost is to have;

<u>8 day-shift</u><u> workers and </u><u>6 night shift </u><u>workers</u>

The given parameter are;

The overlapping shift worked are;

Noon to 8 P.M.

4. P.M. to midnight

\begin{array}{|l|c|c|c|} \mathbf{Time}& \mathbf{12 \ noon \  -\ 4 \ p.m.}& \mathbf{4 \ p.m. \  -\ 8 \ p.m. }& \mathbf{ 8 \ p.m. \ - midnight}\\Employee \ needed&At \ least \ 5&At \ least \ 14 &6\\Hourly \ rate& \$5.50 & \$7.50 & \$7.50 \end{array}\right]

Let <em>x </em> represent the number of day-shift workers required, and let <em>y</em> represent the number of night shift workers required, we have;

x + y ≥ 14

y = 6

x ≥ 5

By plugging in the value of <em>y</em>, gives;

x + 6 ≥ 14

x ≥ 14 - 6 = 8

x ≥ 8

Therefore, the solution for minimal cost that satisfies the constraints is x = 8

We get;

The schedule to minimize the cost is; The number of <u>day-shift workers</u> required, x = <u>8</u>, and the number of <u>night shift workers</u> required, <em>y</em> = <u>6</u>

<u />

Learn more about optimization and linear programming here:

brainly.com/question/13610156

brainly.com/question/20022290

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