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r-ruslan [8.4K]
2 years ago
14

PLEASE HELP QUICK!!!

Mathematics
2 answers:
GrogVix [38]2 years ago
8 0
The answer is 50pi.
Marysya12 [62]2 years ago
4 0

The formula for the volume of a cone is V=\pi r^2\frac{h}{3}

Plug in the values we know.

V=\pi (5)^2\frac{6}{3}

V=\pi*25*2

V=50\pi

V=157

^ If 3.14 was used for \pi

Hope this helps.

頑張って!

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The temperature was 75° Fahrenheit. The temperature dropped at a rate of 10° per hour.
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-5 degrees

Step-by-step explanation:

you started at 75 degrees. it dropped at a rate of 10 degrees per hour. It's been eight hours. 8 times 10 equals 80. It dropped a total of 80 degrees. the starting 75 degrees minus the current 80 degrees equals -5 degrees.

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Solve the system by substitution.<br> -2x + 7y = 15<br> бу = 3
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6 0
2 years ago
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
3 years ago
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