$~~~2x^{16} - 32x^4\\\\ = 2x^4(x^{12} -16)\\\\=2x^4\left[(x^6)^2 - 4^2 \right]\\\\=2x^4(x^6 -4)(x^6 +4)~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=2x^4\left[(x^3)^2 - 2^2\right] (x^6 +4)\\\\=2x^4(x^3 -2)(x^3 +2)(x^6 +4)$

4 0

2 years ago

Independent variable

amm1812

Answer:

The variable that you control, often referred to as the x.

7 0

3 years ago

PLS Help me! This graph shows the outside temperature (in degrees Celsius) over the course of 12 hours, starting at midnight (x

viktelen [127]

Answer:

The domain is the set of all possible x-values

Domain is the time here

The range is the resulting y-values

The range is the outside temperature is here

Function is decreasing between x= 0 to 3

It means the temperature is decreasing between midnight and 3 AM

5 0

3 years ago

I dont understand this

kirza4 [7]

Step-by-step explanation:

first u find the angles and then u use some low divide the length of triangle by sin of opposite angles

4 0

3 years ago