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BabaBlast [244]
2 years ago
14

If you get payed $11.75 an hour, how many hours do you have to work to have $169,000

Mathematics
2 answers:
Leni [432]2 years ago
7 0

Answer:

you would have to work 37.5 hours and dont do it in one sitting i would die it not worth it if you have to do it one sitting XD lol

Step-by-step explanation:

Varvara68 [4.7K]2 years ago
5 0

Answer:

14,382.97 hours

Step-by-step explanation:

169000 / 11.75 = 14,382.97 hours

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Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh
yuradex [85]

Answer:

The northern lighthouse is approximately 24.4\; \rm mi closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as \rm N, the southern lighthouse as \rm S, and the boat as \rm B. These three points would form a triangle.

It is given that two of the angles of this triangle measure 40^{\circ} (northern lighthouse, \angle {\rm N}) and 21^{\circ} (southern lighthouse \angle {\rm S}), respectively. The three angles of any triangle add up to 180^{\circ}. Therefore, the third angle of this triangle would measure 180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ} (boat \angle {\rm B}.)

It is also given that the length between the two lighthouses (length of \rm NS) is 75\; \rm mi.

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, \angle {\rm B} is opposite to side \rm NS, whereas \angle {\rm S} is opposite to side {\rm NB}. Therefore:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}.

Substitute in the known measurements:

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}.

Rearrange and solve for the length of \rm NB:

\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}.

(Round to at least one more decimal places than the values in the choices.)

Likewise, with \angle {\rm N} is opposite to side {\rm SB}, the following would also hold:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}.

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}.

\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}.

In other words, the distance between the northern lighthouse and the boat is approximately 30.73\; \rm mi, whereas the distance between the southern lighthouse and the boat is approximately 55.12\; \rm mi. Hence the conclusion.

4 0
2 years ago
The hypotenuse of a right triangle is 14 centimeters long. One of the legs of the triangle is 6 centimeters. What is the length
BartSMP [9]

Answer: 12.65 cm

Step-by-step explanation:

Use the Pythagoras theorem,

a^2 + b^2= c^2

You are given the hypotenuse , which is c and another leg which is either a or b, does not particularly matter- rearrange to find the missing length

c^2 - b^2 = a^2

14^2 - 6^2 = 160

Square root 160 to find the missing length

12.65

Hope this helped :)

5 0
3 years ago
Find the slope between the following 2 coordinate points. (-3,6) and (-1,-8)
padilas [110]
The slope formula is y2-y1 divided by x2- x1 so -8-6=-14 and -1+3=2
-14/2 =-7
3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!!! PLEASE
Elanso [62]
The given above is are triangles, as per the proof the line segments on top and bottom part are parallel. Also, it is given that two pairs of the angles of the triangles are congruent. 

The triangles also share one common side, CA. Since, this side is between the angles the postulate that will prove the congruence of the triangles is ASA. 

The answer to this item is the third choice. 
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3 years ago
Keiko started a race at 6:44 PM and finished it at 7:13 PM.
KiRa [710]

Answer

29 minutes

Step-by-step explanation:

5 0
3 years ago
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