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3 years ago

What’s the reason 2(x-3)+4=12

Mathematics

2 answers:

Tamiku [17]3 years ago

7 0

Answer:

x =7

Step-by-step explanation:

2(x-3)+4=12 Remove the brackets on the left

2x - 6 + 4 = 12 Combine

2x - 2 = 12 Add 2 to both sides

2x - 2 + 2 = 12 + 2 Combine

2x = 14 Divide by 2

2x/2 = 14/2

x = 7

ryzh [129]3 years ago

6 0

... 2x-6

do u have a other way to sow us

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165° 145 x = Please Help!!!!

Art [367]

Answer:

15°

Step-by-step explanation:

The 165° and x forms a straight line or a supplementary angle. Supplementary angles add up to 180°. Therefore:

$165+x=180$

Solve for x:

$165+x=180\\x=15\textdegree$

4 0

3 years ago

Read 2 more answers

Which is greater thirty six and nine thousandths or four tens

malfutka [58]

Answer:

four tens

Step-by-step explanation:

four tens is greater because:

four tens = 40

thirty six and nine thousandths = 36.009

36.009 < 40

6 0

4 years ago

A rectangular room is 3 meters longer than it is wide, and its perimeter is 26 meters. Find the dimension of the room. The lengt

Juli2301 [7.4K]

Perimeter is the sum of all 4 walls.

Divide the perimeter in half for the total of the width + the length:

26/2 = 13 meters

Subtract the difference in length:

13 - 3 = 10

Divide by 2 walls:

10/2 = 5

The width is 5 metes.

The length is the 5 metes + the 3 meter difference = 5 +3 = 8 meters.

The length is 8 meters and the width is 5 meters.

5 0

3 years ago

Please help me please!!

AysviL [449]

Answer:

198 degrees

Step-by-step explanation:

3 0

3 years ago

Find the work required to move an object in the force field F = ex+y <1,1,z> along the straight line from A(0,0,0) to B(-1

storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field

$\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})$

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t) with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

$\large W=\int_{C}Fdr$

where C is the segment that goes from A to B.

$\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt$

Integrating by parts the last integral:

$\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1$

and

$\large \boxed{W=\int_{C}Fdr=e+24}$

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

$\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1$

The segment that goes from (1,0,0) to B can be parameterized as

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

$\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}$

Hence, the work required to move the particle from A to B along D is

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

6 0

4 years ago