29) First of all when I write “^2” I mean to the power of 2. Label the bottom line Z or whatever u fancy. Then make 3 equations to solve simultaneously using a^2+b^2=c^2
(1) 14^2+y^2=Z^2
(2) 6^2+y^2=x^2 and (3) x^2+z^2=20^2
The next step is to solve them simultaneously e.g you can rearrange (2) to give you y^2=x^2-6^2 and then input that into (1) to get 14^2+x^2-6^2=Z^2 and again you rearrange (3) to get z^2=20^2-x^2 and input that in and solve for x. Then you will have to repeat that solving for y and only y as the question doesn’t originally ask for z but only for the values of x and y I assume. Using this idea, from glancing at the other questions you should be able to apply this concept to those other questions, if not then make another post outlining any specific questions
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
BB' = 6
B'A = 2
Step 02:
scale factor:

The answer is:
scale factor = 3
Hi there! :)
Answer:

<u><em>*THE ANSWER MUST HAVE A NEGATIVE SIGN!*</em></u>
Step-by-step explanation:
First, you subtract by 8 from both sides of an equation.
5x+8-8=9x+12-8
Subtract.
12-8=4
5x=9x+4
Then, you subtract by 9x from both sides of an equation.
5x-9x=9x+4-9x
Simplify by equation.
-4x=-4
Divide by -4 from both sides of an equation.
-4x/-4=-4/-4
Divide by the numbers from left/right.
-4/-4=-1
, <em>is the FINAL/CORRECT ANSWER! :)</em>
<em>Have a nice day! :)</em>
<em>:D</em>
<em>-Charlie</em>
<em>Thank you!</em>
I think your answer would be 23/93 hope I helped :D
Answer:
unclear man, u cant add them together sorry
Step-by-step explanation: