<u>Solution-</u>
From the figure,
AE = 2.4
EB = 2.8
BC = 11.7
Area of rectangle 1 = 8.68 sq.in
(∵ sides of the rectangle 2)
Area of Triangle 1 = 6.48 sq.in
(∵ sides of the rectangle 1)
(∵ sides of the rectangle 2)
The area of Rectangle 2,
The area of Triangle 2,
The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2
= 6.48+8.68+8.82+6.44=30.42 sq.in
Answer:
If I'm doing the problem correctly, the radius should be 4 yards.
Step-by-step explanation:
You work the problem backwards. Multiply 200.96 by 3, since it's a cone, so you're working with the volume of what a cylinder would be with the same dimensions. Then divide by the height (12 yd), then divide by pi. You should end up with 16, and 4 squared equals 16. Work the problem forwards from there to check.
4 squared is 16. 16 times 3.14 is 50.24. 50.24 times 12 is 602.88. 602.88 divided by 3 is 200.96.
Answer:
(-2,1)
Step-by-step explanation:
The solution is where the two equations/lines intersect, which is at (-2,1)
Answer:
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