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makvit [3.9K]
3 years ago
11

Need help with this math

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

43112

its a random number

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Find the inverse of the following function.
Naddik [55]

For this case we must find the inverse of the following function:

f (x) = 8 \sqrt {x}

For this, we follow the steps below:

We change f (x) to y:

y = 8 \sqrt {x}

We exchange the variables:

x = 8 \sqrt {y}

We solve for y:

8 \sqrt {y} = x

We divide between 8 on both sides of the equation:

\sqrt {y} = \frac {x} {8}

We raise both sides of the equation to the square to remove the root:

y = (\frac {x} {8}) ^ 2\\y = \frac {x ^ 2} {64}

So, the inverse is:f ^ {- 1} (x) = \frac {x ^ 2} {64}

ANswer:

Option C

3 0
3 years ago
Kyles net worth is 500
iren [92.7K]
What is the question?
8 0
3 years ago
Read 2 more answers
How many and what type of solutions does the equation have?<br><br> 2k² = 9 + 3k
anzhelika [568]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3×-y=5,2×+y=5 pleaseplease ​
Tanya [424]

Answer:

x = 2

y = 1

Step-by-step explanation:

3x - y = 5..............(1)× 1

2x + y = 5...….......(2)× 1

3x - y = 5..............(3)

2x + y = 5.............(4)

Cancel y

3x + 2x = 5 + 5

5x = 10

Divide both sides by 5

x = 2

Substitute for the value of y

3x - y = 5

3(2) - y = 5

6 - y = 5

6 - 5 = y

1 = y

y = 1

6 0
3 years ago
Consider the equation x2+4x+9=0 in standard form. Which equation shows the coefficients a, b, and c correctly substituted into t
Afina-wow [57]

Answer:

<h2>x = -2+i√5 and  -2i-√5</h2>

Step-by-step explanation:

The general form of a quadratic equation is ax²+bx+c = 0

Given the quadratic equation x²+4x+9=0 in its standard form, on comparing with the general equation we can get the value of the constant a, b and c as shown;

ax² = x²

a = 1

bx = 4x

b = 4

c = 9

The quadratic formula is given as x = -b±√(b²-4ac)/2a

Substituting the constant;

x = -4±√(4²-4(1)(9))/2(1)

x = -4 ±√(16-36)/2

x = -4±√-20/2

x = -4±(√-1*√20)/2

Note that √-1 = i

x = -4±(i√4*5)/2

x = (-4±i2√5)/2

x = -4/2±i2√5/2

x = -2±i√5

The solution to the quadratic equation are  -2+i√5 and  -2i-√5

5 0
3 years ago
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