STEP 1:
find the sales tax (decimal form)
x= sales tax
Cost + (Cost * Sales Tax)= Total
plug in known numbers
$9.40 + ($9.40 * x)= $9.87
9.40 + 9.40x= 9.87
subtract 9.40 from both sides
9.40x= 0.47
divide both sides by 9.40
x= 0.47/9.40
x= 0.05 sales tax decimal form
STEP 2:
find sales tax percentage
= 0.05 * 100
or move decimal to the right two decimal places
= 5% sales tax percent form
ANSWER: The sales tax is 5% (or 0.05 in decimal form)
Hope this helps! :)
Answer:

Step-by-step explanation:
The given line passes through: (0,-3), (2,0), and (4,3).
We first of all find the slope using 
Using
we find the slope to be

The equation is given by
, where
is the slope and c=-3 is the y-intercept.
Therefore the equation is 
Answer:
-4 and -2
Step-by-step explanation:
First find all the factors of 8, that would be 1 and 8, -1 and -8, 2 and 4, and -2 and -4.
Then, adding the groups of numbers you have should show you what would equal -6. So 1 + 8 = 9, -1 + (-8) = -9, same vice versa, 2 + 4 = 6, -2 + (-4) = -6. So -2 and -4 would be your two numbers.
I don't see the steps, but the steps that I use are:
1. Multiply the denominator by the whole number
2. Then you add the numerator to your sum.
3. The number that you just got by doing those steps is now going to be your numerator and your old denominator is going to stay your denominator.
Example:
2 2/3
3*2=6
6+2=8
8/3 is your new answer.
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Quotient Rule]: ![\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5D%3D%5Cfrac%7Bg%28x%29f%27%28x%29-g%27%28x%29f%28x%29%7D%7Bg%5E2%28x%29%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Rule [Quotient Rule]:

- Basic Power Rule:

- Exponential Differentiation:

- Simplify:

- Rewrite:

- Factor:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation