For this case we have to define root properties:
![\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20n%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bn%7D%20%7Bn%7D%7D%20%3D%20a)
In addition, we know that:
![a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}](https://tex.z-dn.net/?f=a%20%5E%20%7B-%201%7D%20%3D%20%5Cfrac%20%7B1%7D%20%7Ba%20%5E%201%7D%20%3D%20%5Cfrac%20%7B1%7D%20%7Ba%7D)
On the other hand:
![4 ^ 2 = 16](https://tex.z-dn.net/?f=4%20%5E%202%20%3D%2016)
Thus, we can rewrite the given expression as:
![\sqrt {4 ^ 2 * a ^ 8 * \frac {1} {b ^ 2}} =\\4 ^ {\frac {2} {2}} * a ^ {\frac {8} {2}} * \frac {1} {b ^ {\frac {2} {2}}} =\\4 * a ^ 4 * \frac {1} {b}](https://tex.z-dn.net/?f=%5Csqrt%20%7B4%20%5E%202%20%2A%20a%20%5E%208%20%2A%20%5Cfrac%20%7B1%7D%20%7Bb%20%5E%202%7D%7D%20%3D%5C%5C4%20%5E%20%7B%5Cfrac%20%7B2%7D%20%7B2%7D%7D%20%2A%20a%20%5E%20%7B%5Cfrac%20%7B8%7D%20%7B2%7D%7D%20%2A%20%5Cfrac%20%7B1%7D%20%7Bb%20%5E%20%7B%5Cfrac%20%7B2%7D%20%7B2%7D%7D%7D%20%3D%5C%5C4%20%2A%20a%20%5E%204%20%2A%20%5Cfrac%20%7B1%7D%20%7Bb%7D)
ANswer:
Option B
Firstly, seeing that the sequence is based on odd numbers I would say that this is the formula (which will allow you to know whatever term):
nth term = 2n-1
Hope this helps!
<h3> </h3><h2> F-{1} (x)= x/6 + 5/6</h2>
Answer:
16.5 =x
Step-by-step explanation:
Since this is a right triangle, we can us trig functions
tan theta = opp side / adjacent
tan 70 = x /6
Multiply each side by 6
6 tan 70 = x
16.48486452 =x
To the nearest tenth
16.5 =x