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3 years ago

FInd mPQ Geometry question, circles, arc length, chord length,

Mathematics

1 answer:

Fed [463]3 years ago

3 0

Answer:

$\text{B. }26}$

Step-by-step explanation:

Since $\overline{PN}$ and $\overline{PQ}$ are equal, we can set them equal to each other:

$7x+5=10x-4,\\9=3x,\\x=3$

Substitute $x=3$ to solve for $\overline{PQ}$ :

$\overline{PQ}=10(3)-4=\boxed{\text{B. }26}}$

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Alex made an eyeglass case and sold it for $12.00. He spent $1.29 on felt and $2.75 on a needle and thread. What was his profit?

madreJ [45]

D because 1.29 plus 2.75 is 4.04(the money that he used to make the case) and subtract that with $12 and you get $7.96 as the profit.

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2 years ago

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1/6 + 3/8 <br> A. 4/6<br> B. 4/8 <br> C. 4/14<br> D. 13/24

Naddika [18.5K]

Here is you're answer:

In order to get you're answer you need to find the common denominator then add.

$\frac{1}{6} + \frac{3}{8}$
Find the common denominator:
$CD = 48$
$= \frac{26}{48}$
Simplify:
$\frac{26}{48} \div 2 = \frac{13}{24}$
$= \frac{13}{24}$

Therefore you're answer is option D "13/24."

Hope this helps!

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2 years ago

Solve 765/14 and write your answer in terms of a mixed number (please use this format: 75 3/5). *

polet [3.4K]

Answer:

The answer is 54 9/14

Step-by-step explanation:

what u do is this

#1. 765 divided by 14 which equals 54.64285714. Don't worry about the numbers after the decimal.

Then u do 65-54= 9 so u have 54 9/14

to check yourself just do 14 times 54= 756 + 9 = 765

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2 years ago

Help with this math question

tresset_1 [31]

The given inequality is:

$|-8x+24| \leq 16$

This inequality can be divided in two parts as:

a) $-16 \leq -8x +24$
b) $-8x + 24 \leq 16$

Solving part a:

$-16 \leq -8x+24 \\ \\ 
-40 \leq -8x \\ \\ 
5 \geq x \\ 
or \\ 
x \leq 5$

Solving part b:

$-8x+24 \leq 16 \\ \\ 
-8x \leq -8 \\ \\ 
x \geq 1$

Therefore, the solution to the given inequality is $x \leq 5$ and $x \geq 1$ . Combining both the ranges we get the solution: $1 \leq x \leq 5$ .

In interval notation, this solution can be expressed as [1,5]

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3 years ago

Read 2 more answers

The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15

zzz [600]

In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05

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3 years ago