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3 years ago

15

He bought a boat for 24000 in the year 2009. The value of the boat depreciated linearly. If the value of the boat in 2010 was 18

500,what was the annual rate of change of the boats value?

1 answer:

Lady bird [3.3K]3 years ago

7 0

Answer:

-$5,500

Step-by-step explanation:

The change in the one year from 2009 to 2010 was ...

18,500 -24,000 = -5,500

The annual rate of change in the boat's value was -$5,500.

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Answer:

The answer is

<h2> $- \frac{6}{7}$ </h2>

Step-by-step explanation:

The slope of the line passing through two points can be found by using the formula

<h3> $m = \frac{y2 - y1}{x2 - x1}$ </h3>

where

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From the question

The points are (-2,5) and (3/2, 2)

The slope is

<h3> $m = \frac{2 - 5}{ \frac{3}{2} + 2} \\ = - \frac{3}{ \frac{7}{2} } \\ = - 3 \div \frac{7}{2} \\ = - 3 \times \frac{2}{7}$ </h3>

We have the final answer as

<h3> $- \frac{6}{7}$ </h3>

Hope this helps you

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3 years ago