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3 years ago

11

1. Ben rents a car for one day. The charge is $20 plus the $0.12 per mile. He wants to spend exactly $80. How many miles can he

drive?

1 answer:

Darya [45]3 years ago

8 0

Answer:

500

Step-by-step explanation:

80-20=60

60/0.12=500

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malfutka [58]

First one should be B

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4 years ago

Read 2 more answers

Cory earns $20 per day plus $6 for every

Lorico [155]

Answer:

A. at least 5 sales

Step-by-step explanation:

if he is already making $20 dollars each day and he wants $50 on friday I first took 50-20 to find what he needs to make just in sales once I found out he needs $30 so then I divided 30 by 6 to find out exactly how many sales he needs to make.

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3 years ago

What is an equation of the line that passes through the points (-6, 5) and (6, 7)?

e-lub [12.9K]

Answer:

$y=\frac{1}{6}x+6$

Step-by-step explanation:

Let $(x_1,y_1)\rightarrow(-6,5)$ and $(x_2,y_2)\rightarrow(6,7)$

<u>Determine slope</u>

<u /> $m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{7-5}{6-(-6)}\\ \\m=\frac{2}{6+6}\\ \\m=\frac{2}{12}\\ \\m=\frac{1}{6}$

<u>Use either ordered pair to find the y-intercept</u>

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3 years ago

Julian measuredthe distance around a small fishpond as 27 yards. which would be a good estimate for the distance across the pond

agasfer [191]

9 yards would be a good estimate for the distance across the pond.

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4 years ago

The amount of time a certain brand of light bulb lasts is normally distributed with a

scoundrel [369]

Answer:

92.65 % light bulbs last less than 2080 hours

Step-by-step explanation:

We are given that The amount of time a certain brand of light bulb lasts is normally distributed

Mean = $\mu = 2000$

Standard deviation = $\sigma = 55$

We are supposed to find What percentage light bulbs last less than 2080 hours, to the nearest tenth

$Z = \frac{x-\mu}{\sigma}\\\\Z=\frac{2080-2000}{55}$

Z=1.45

Refer the z table for p value

p value = 0.9265

Hence 92.65 % light bulbs last less than 2080 hours

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3 years ago