Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.
has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half
Answer:
Ramon's mistake was that he used whole numbers in comparison to decimals, which is not an accurate way to solve. Think about it this way, 0.1 is the tens place, 0.01 is the hundreds place. Which would be greater 100% of the time? The hundreds place, in decimal terms, the hundredths.
0.09 is greater than 0.1
Answer:
y=q(x-r)+p
Step-by-step explanation:
y-y1=m(x-x1)
y-p=q(x-r)
y=qx-qr+p
y=q(x-r)+p
Answer:
140
Step-by-step explanation:
so where trying to find the unknown total of coins so where gonna call that x
then we will make an equation 5% * x= 7
then to make it easier to solve we will convert 5% to a decimal .05
and finally to find the answer we will divide both sides by .05
this gives us x= 140 which is the answer