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3 years ago

Please help ASAP ASAP

Mathematics

2 answers:

Marrrta [24]3 years ago

4 0

I can’t see it it’s blurry to me

Oksanka [162]3 years ago

4 0

I can’t see to it’s blurry

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Which value of y makes the inequality 3y^2 +2(y-5)>8 true?

Alex

Answer: D

Step-by-step explanation:

A) 3*0^2+2(0-5)>8

-10>8 -> not true

B) 3*(-1)^2+2(-1-5)>8

3*1+2*(-6)>8

3- 12>8

-9> 8 -> not true

C) 3*(-2)^2+2(-2-5)>8

3*4+2*(-7)>8

12-14>8

-2> 8 -> not true

D) ) 3*(-3)^2+2(-3-5)>8

3*9+2*(-8)>8

27-16>8

11> 8 -> true

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3 years ago

James is participating in a 5-mile walk to raise money for a charity. he has received $200 in fixed pledgesand raises $20 extra

xxMikexx [17]

5x20=100 100+200=300 or atlas what i think if this is wrong i am sry but if isn't I'm glad I'm able to help ^u^

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3 years ago

X-intercept =2; y-intercept =4/3 Find he equation of the line

Neko [114]

Y = mx + b
plug in the numbers.
y = 4/3 + 2

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3 years ago

Write the equation of the parabola in vertex form.

stellarik [79]

well, looking at the picture of this vertically opening parabola, it has a vertex at 0,0 and it passes through 2,1 hmm ok

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = a(x-0)^2+0\qquad \stackrel{\textit{we also know that}}{x=2\qquad y = 1}\qquad \implies 1=a(2-0)^2+0 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hspace{10em} \boxed{y=\cfrac{1}{4}x^2}$

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2 years ago

HELP ASAP!!

vesna_86 [32]

Answer:

13.73 in^2 because the circle's area is 50.27 in^2

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3 years ago