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What is the slope intercept form when m = 1/2 & b = 89 ?<br> Helppppppppp

Zina [86]

Answer:

$y = \frac{1}{2}x + 89$

Step-by-step explanation:

slope-intercept form: y = mx + b

y = (x , y)

x = (x , y)

m = slope = 1/2

b = y-intercept = 89

Plug in the corresponding numbers & variables to the corresponding variables:

y = (1/2)x + 89

$y = \frac{1}{2}x + 89$ is your answer.

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5 0

3 years ago

Read 2 more answers

F(x)=4x+1 and g(x)=x^2-5find(f-g)(x)

Vinvika [58]

Answer:

Step-by-step explanation:

Given f(x)=4x+1 and g(x)=x²-5

(f-g)(x) is derived by taking the difference of both functions

(f-g)(x) = f(x)-g(x)

(f-g)(x) = 4x+1 - (x²-5)

(f-g)(x) = 4x+1-x²+5

(f-g)(x) = -x²+4x +6

This gives the requires expression

4 0

3 years ago

You have a credit card with an initial balance of $3,168.00 and an interest rate of 12.75% apr. if you make no payments on the c

zaharov [31]

A=p(1+i/m)^mn
P=3168
i=0.1275
M=12
n=3/12
A=3,168×(1+0.1275÷12)^(12*3/12)
A=3,270.06

7 0

3 years ago

Read 2 more answers

Together, teammates Pedro and Ricky got 2679 base hits last season. Pedro had 283 more hits than Ricky. How many hits did each p

Sergio [31]

Answer:

Pedro: 1481 Base hits

Ricky: 1198 Base hits

Step-by-step explanation:

First, take the total amount of base hits last season 2679, then subtract how many more Pedro has 283.

2679 - 283 = 2396 now divide the sum in half 2396 ÷ 2 = 1198 that gives you how many each player has, you're then going to add the amount that you took off to only Pedras total since he had 283 more

Pedro: 1198 + 283 = 1481

Ricky: 1198

3 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$