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krek1111 [17]
3 years ago
6

2(6k+8)-6k=4 What is the answer

Mathematics
1 answer:
lina2011 [118]3 years ago
7 0

Answer:

k=-2

Step-by-step explanation:

2(6k+8)-6k=4

12k+16-6k=4

6k+16=4

6k=-12

k=-2

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HURRY HELP! ILL MARK BRAINLEST ANSWER!!! if I have an 82 in a class, and I get 100 on two projects worth 15% of my grade, what w
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Answer:

Your final grade would be 87.4

Step-by-step explanation:

When an assessment is worth a certain percentage of a final grade, the grade percentage of the assessment is taken from its allocated percentage of the final grade. For example:

One project is worth 15% of the final grade, and you got 100% on it. This means that the percentage it contributes to the final grade is 100% (achieved) of 15% (allocated %). 100% of 15% is 15% (15x1). This means that if you hypothetically only completed the project 100% without other assessments, your final grade would be 15%.

This is the same for the other project: 100% (achieved) of 15 (% worth of final grade) = 15.

This is because when you get 100% on the project, you get the full 15% of its worth for the final grade (if that makes sense).

So, from both projects, the final grade would be 30.

Now for the 82.

Since the projects together are worth 30% of the final grade, it means that the 82 in class is worth the remaining 70%.

82% (achieved) of 70 (worth %) = 70x0.82 = 57.4

The 82 in class contributes 57.4 towards the final grade.

Since we have 30 from the projects, and the 57.4 from the class, your final grade would be 30+57.4 = 87.4

Hope this helped!

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