ABCD 1234 AEIOU = meow meow i’m not a cow who who
Answer:
a: 0.9544 9 within 8 units)
b: 0.9940
Step-by-step explanation:
We have µ = 300 and σ = 40. The sample size, n = 100.
For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:
P(292 < x < 308).
We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.
We have P(292 < x < 308) = 0.9544
Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311. We want to find
P(289 < x < 311)
We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.
We have P(289 < x < 311) = 0.9940
Answer:
-2.5625
Step-by-step explanation:
<u>1)[-1/4/5] × [-7/10+0.95] - [-2/1/4] turn that into improper fractions</u>
2 1/4=9/4
which is 1 4/5(-7/10+0.95)9/4
<u>2) 1 4/5(-7/10+0.95)= 0.3125</u>
which is 0.3125-9/4
<u>3)Make into decimal form</u>
9/4 equals 2.25
which is 0.3125-2.25
which all equals -2.5625
Given a quadratic equation
, we define the discriminant as

The number of real solutions of the equation depend on the sign of
:
- If
the equation has two solutions - If
the equation has one double solution - If
the equation has no real solutions
In this case, we have

And so this equation has no real solutions.
Consider, pls, this solution.
Note, that V1 marked with orange lines (see the graph), V2 - with green colour.