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Vika [28.1K]
3 years ago
10

Can anybody help me with qn 6b?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
400% • x = 1
400/100 • x = 1
4x = 1
Divide each side by four.
4x/4 = ¼
x = ¼

The value of x is ¼.
3241004551 [841]3 years ago
6 0
Since 400% is essentially 4 times as much of something, this is 4x = 1.  Therefore, x =  \frac{1}{4}
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On Thursday the basketball coach ordered 12 pizzas for 36 players who came in for practice. How many pizzas does the coach need
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Answer:16

Step-by-step explanation:Next day there will be (36+12) or 48 players.

For 36 players 12 pizzas are needed

For 1 player 12/36 pizzas are needed

For 48 players 12/36*48 or 16 pizzas are needed

3 0
2 years ago
Draw the following scenario using a vertical number line.
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You would move your point 24 up from the starting point then move it three down from the 24 so if you start at zero go to 24 then move it down to 21.

3 0
3 years ago
What is an equation of a circle with center (2, -1) that passes through the point (3, 4)?
Svet_ta [14]

Answer:

<em>(x - 2)^2 + (y + 1)^2 =  26</em>

Step-by-step explanation:

A circle with center O(2, -1) that passes through the point A(3, 4).

=> The radius of this circle is OA which could be calculated by:

OA = sqrt[(3 - 2)^2 + (4 - (-1))^2] = sqrt[1^2 + 5^2] = sqrt[26]

The equation of a circle with center O(a, b) and radius r could be written as:

(x - a)^2 + (y - b)^2 = r^2

=> The equation of circle O above with center O(2, -1) and radius = sqrt(26) is shown as:

    (x - 2)^2 + (y - (-1))^2 = (sqrt(26))^2

<=>(x - 2)^2 + (y + 1)^2 = 26

Hope this helps!

4 0
2 years ago
Read 2 more answers
Solve 5x^2 - 7x + 2 = 0 by completing the square.
Reika [66]

Answer:  The correct option is (c) \dfrac{49}{100}.

Step-by-step explanation:  We are given to solve the following quadratic equation by the method of completing the square:

5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

So,

x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

Thus, the required solution is x=1,~-\dfrac{2}{5}. and the value of the constant added is \dfrac{49}{100}.

Option (c) is correct.

3 0
2 years ago
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