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3 years ago

PLEASE I DESPERATELY NEED HELP MY ASSIGNMENT IS DUE TOMORROW I WILL MARK YOU AS BRAINLIEST WHOEVER ANSWERS FIRST PLEASEEEEE

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:

Store B

Step-by-step explanation:

There is 3 feet in a yard and at $3.06 a yard is $1.02 a foot. Store A is $1.10 a foot.

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On #10 i need help to solve this. please and thank you.

valina [46]

10a. $f(x) = x - 4$
   $h(x) = \sqrt{x - 5}$
   $(f - h)(6) = (6 - 4) - (\sqrt{6 - 5})$
   $(f - h)(6) = 2 - \sqrt{1}$
   $(f - h)(6) = 2 - 1$
   $(f - h)(6) = 1$

10b. $f(x) = x - 4$
   $g(x) = \frac{1}{x - 3}$
   $(f * g)(x) = (x - 4)(\frac{1}{x - 3})$
   $(f * g)(x) = \frac{x - 4}{x - 3}$
   Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
   Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = \frac{1}{x - 3}$
   $h(x) = \sqrt{x - 5}$
   $(g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})$
   $(g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}$

10d. $f(x) = x - 4$
   $g(x) = \frac{1}{x - 3}$
   $h(x) = \sqrt[3]{x - 7}$
   $h(x) = (f * g)(x)$
   $\sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})$
   $\sqrt[3]{x - 7} = \frac{x - 4}{x - 3}$
   $(\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}$
   $x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}$
   $(x - 3)^{3}(x - 7) = (x - 4)^{3}$
   $(x^{3} - 9x^2 + 27x + 27)(x - 7) = (x^{3} - 12x^{2} + 48x - 64)$
   $x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64$
   $x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64$
   $x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64$
   $x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64$
   $x^{4} + 102x^{2} + 253 = 17x^{3} + 264x$
   $x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0$
   $x = 4\ or\ 8$

4 0

3 years ago

If a=2b then a:b= what ???

cluponka [151]

Answer:

$2:1$

Step-by-step explanation:

$a:b\\---\\\ 2b:b\\2:1$

5 0

3 years ago

PLEASE ANSWER ASAP, I AM TIMED

Triss [41]

the answer could be 360,000.

8 0

4 years ago

Read 2 more answers

Ok.......................................................

quester [9]

Answer:

Hello there do you need help, if so what is he problem:)

Step-by-step explanation:

7 0

3 years ago

Sat question solve<br><br> 2^x=x^2

Ivan

The logarithm function can be used to convert large problem of multiplication and division into simple addition or subtraction. The value of x for the given equation is 2.

<h3>What is Logarithm? </h3>

Logarithm function is defined as the inverse of the exponential function.

If a^(b) = c, then b = log(c) at the base of a.

The given equation is as below,

2^x=x^2

Take logarithm both sides,

x log(2) = 2 log(x)

=> x / log(x) = 2 / log(2)

Compare the denominator and numerator at both sides of the equation to get,

x = 2.

Hence the solution of the given equation is x = 2.

To know more about logarithm click on,

brainly.com/question/20785664

#SPJ1

7 0

1 year ago