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Aleonysh [2.5K]
3 years ago
13

(ar^b) ^4 = 16r^20 where a and b are positive integers work our a and b​

Mathematics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

a = 2

b = 5

Step-by-step explanation:

Given :

(ar^b)^4 = 16r^20 ; a and b are positive integers :

Opening the bracket :

a^4r^4b = 16r^20

a^4 = 16 - - - - - (1)

r^4b = r^20 - - - (2)

a^4 = 16

Take the 4th root of both sides :

(a^4)^(1/4) = 16^1/4

a = 2

From (2)

r^4b = r^20

4b = 20

Divide both sides by 4

4b/4 = 20/4

b = 5

Hence ;

a = 2

b = 5

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Step-by-step explanation:

Since adding a positive makes a negative number stay negative, it equals -4.

Then by subtracting a negative with a positive (5), the number stays negative once again, which then equals -10.

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Given:

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The measure of arc AD and measure of each arc.

Solution:

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Step-by-step explanation:

In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.

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