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3 years ago

What is a 5th of a kilogram

Mathematics

2 answers:

irinina [24]3 years ago

6 0

One 5th of a kilogram is 200. <span />

julia-pushkina [17]3 years ago

6 0

5th? Oh, OK. 1000/5=200. I think I mean...

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H(w)=-5x^2+80 to factored form

algol13

Answer:

- 5(x - 4)(x + 4)

Step-by-step explanation:

Given

- 5x² + 80 ← factor out - 5 from each term

= - 5(x² - 16) ← x² - 16 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

x² - 16 = x² - 4² = (x - 4)(x + 4)

Thus

- 5x² + 80 = - 5(x - 4)(x + 4) ← in factored form

3 0

3 years ago

What is the derivative of w=(t^2+1)^100<br><br> How is it 200t(t^2+1)^99?

GuDViN [60]

(t^2+1)^100

USE CHAIN RULE

Outside first (using power rule)

100*(t^2+1)^99 * derivative of the inside

100(t^2+1)^99 * d(t^2+1)

100(t^2+1)^99 * 2t

200t(t^2+1)^99

6 0

3 years ago

Read 2 more answers

3x^2yz^3-9x^3y^2z^2+12x^2y^3z^2

PolarNik [594]

3×2=692047 82837=284749×2484r133.e9274

6 0

2 years ago

Question 1

mamaluj [8]

Answer:

The maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.

Step-by-step explanation:

Given : A total of 1,000 BTUs are needed to cool a space. If 2.5 BTUs are needed to cool 1 cubic foot of space.

To find : What is the maximum volume of space that 1,000 BTUs will cool?

Solution :

Applying unitary method,

2.5 BTU are needed to cool 1 cubic foot of space.

So, 1 BTU are needed to cool $\frac{1}{2.5}$ cubic foot of space.

Then,1000 BTU are needed to cool $\frac{1}{2.5}\times 1000$ cubic foot of space.

i.e. 1000 BTU are needed to cool 400 cubic foot of space.

Therefore, the maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.

4 0

2 years ago

PLEASE HELP ME!!!!!

sergeinik [125]

Proportional because it is constantly adding .99¢

8 0

2 years ago

Read 2 more answers