What is a 5th of a kilogram
2 answers:
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Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean =
Standard deviation =
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)
Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
A and c are parallel to each other and b is perpendicular to both a and c.
