Ask question

Ask question

All categories

3 years ago

15

3 includes of snow in 5 hours?

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

3 TIMES 5

Step-by-step explanation:

You might be interested in

Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem ha

Aleks [24]

Answer:

12

Step-by-step explanation:

The computation of the size of the customers is shown below:

Here we find the greatest common divisor of the given numbers

96, 60, 84 ÷ 2

48, 30, 42 ÷ 2

24, 15, 21 ÷ 2

12, 15, 21 ÷ 2

6, 15, 21 ÷ 2

3, 15, 21 ÷ 3

1, 5, 7 ÷ 5

1, 1, 7 ÷ 7

1, 1, 1

By this there are three numbers i.e. 2, 2 and 3

So, the lease common denominator is

= 2 × 2 × 3

= 12

6 0

2 years ago

Does anyone know this answer

Rzqust [24]

Answer:

c

Step-by-step explanation:

took test

4 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Rut gon cac phan so sau36\63 30\25 24\32 15\30

Stels [109]

2348833bdjdjfjfj ududdu

4 0

2 years ago

Worth 10 points please help me ASAP

Nitella [24]

(2,-2) would be the answer I think

8 0

2 years ago