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maria [59]
3 years ago
14

X=? what’s the answer

Mathematics
2 answers:
Karolina [17]3 years ago
8 0

I hope it will help you .

Thank you.

^ - ^

ludmilkaskok [199]3 years ago
7 0

Answer:

i believe its 4

Step-by-step explanation:

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You need 2 3/4 wheelbarrows of sand to make 8 wheelbarrows of concrete. how much sand will you need to make 248 cubic feet of co
horsena [70]
8 ÷ (2 3/4) = 32/11

248 ÷ (32/11) = B. 85 1/4 cubic feet
6 0
3 years ago
Read 2 more answers
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
The totals of the rows and colums of a two way table are called marginal distributions. true or fasle​
Furkat [3]

Answer:

False

Step-by-step explanation:

The totals of the rows and columns of a two way table are not called marginal distributions. They are called conditional distributions.

4 0
3 years ago
1. If a triangle of area 95 square units has a height of length 19 units, calculate
Anna [14]
48 I believe :) pls like I need points
8 0
2 years ago
A factory inspector found flaws in 3 out of 18 wooden boxes what is the experimental probability that the next wooden box will b
Sphinxa [80]

Answer:

16.666% would be flawed.

Step-by-step explanation:

7 0
3 years ago
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