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malfutka [58]
3 years ago
10

Simplify 3(y-1)+7 completely

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

3y + 4

Step-by-step explanation:

3(y-1) +7

3y -3 +7

3y +4

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Which algebraic function has a smaller rate of change than the equation?<br><br> f(x)=2x−9
vredina [299]
It will be the second option i believe
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Find the product 12 , -5
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The product of 12 and -5 is -5(12) = -60.  Note that 12(-5) = -60 also.
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3 years ago
How can I find a?<br> (Trigonometric Ratios)
earnstyle [38]

Step-by-step explanation:

Hey there!

<u>Use</u><u> </u><u>cos</u><u> </u><u>ratio to</u><u> </u><u>find </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>'</u><u>a'</u><u>.</u>

As per given, we can state that it is a Right angled triangle, so taking 38° reference angle.

We get;

p = AC

b = 6

and h= a

Here, <u>Use</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>b</u><u>,</u><u> </u><u>h</u><u> </u><u>and</u><u> </u><u>3</u><u>8</u><u>°</u><u> </u><u>angle</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u>.</u>

\cos(38° )  =  \frac{b}{h}

\cos(38°)  =  \frac{6}{a}

0.7881 =  \frac{6}{a} [ cos(38°=0.7881]

0.7881a = 6

a =  \frac{6}{0.7881}

Therefore the measure of a is 7.61 Or 8.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
Guys I need help on number 19 and 20.
fenix001 [56]

vdidnrnrreherirrirjrjr

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20
ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

    \sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}

    \sf a^{-m}=\dfrac{1}{a^m}

       First convert radical form to exponent form and then apply exponent law.

 \sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}

\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}

                      = \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}

3 0
2 years ago
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