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jeka57 [31]
3 years ago
13

Can someone please help me ASAP

Mathematics
2 answers:
butalik [34]3 years ago
8 0

Answer:

option D is the correct answer.

Step-by-step explanation:

Naya [18.7K]3 years ago
7 0
Correct answer is D
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Lyla made a scale drawing of a city park. She used the scale 1 millimeter = 1 meter. What is the scale factor of the drawing?
sertanlavr [38]

Answer:

1ml : 1m

Step-by-step explanation:

The scale factor of the drawing is the ratio of 1 milliliter and 1 meter; that is, 1ml : 1m.

4 0
3 years ago
Find the cube root of 27d3 + 54a2b + 36ab2 + 8b3​
enot [183]

Answer:

 (3a + 2b)3

Step-by-step explanation:

STEP 1  :

Equation at the end of step 1

 (((27•(a3))+((54•(a2))•b))+(36a•(b2)))+23b3

Step 2:

(((27•(a3))+((54•(a2))•b))+(22•32ab2))+23b3

Step 3:

(((27•(a3))+((2•33a2)•b))+(22•32ab2))+23b3

Step 4:

 ((33a3 +  (2•33a2b)) +  (22•32ab2)) +  23b3

Step 5:

 Factoring:  27a3+54a2b+36ab2+8b3

8 0
3 years ago
Use Euler's formula to find the missing number.
Damm [24]
The answer to your question is 24
4 0
3 years ago
Read 2 more answers
35 more than twice the value of e is 65
almond37 [142]


here is what I think since 2 multiplied by 15 equals 30 you at 35 more to that 30 and you get the answer 60. Is that how it is supposed to go?


5 0
3 years ago
If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
\implies f(x)=\dfrac1{(1-x)^2}
5 0
3 years ago
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