Answer:
Here we have the domain:
D = 0 < x < 1
And we want to find the range in that domain for:
1) y = f(x) = x
First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)
f(0) = 0 is the minimum in the range.
f(1) = 1 is the maximum in the range.
The range is:
0 < y < 1.
2) y = f(x) = 1/x.
In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.
f(0) = 1/0 ---> ∞
f(1) = 1/1
Then the range is:
1 < x.
Notice that we do not have an upper bound.
3) y = f(x) = x^2
This function is strictly increasing, then:
f(0) = 0^2 = 0
f(1) = 1^2 = 1
the range is:
0 < y < 1
4) y = f(x) = x^3
This function is strictly increasing in the interval, then:
f(0) = 0^3 = 0
f(1) = 1^3 = 1
the range is:
0 < y < 1.
5) y = f(x) = √x
This function is well defined in the positive reals, and is strictly increasing in our domain, then:
f(0) = √0 = 0
f(1) = √1 =1
The range is:
0 < y < 1
<u><em>Answer: 1/11 and 0.09=0.10</em></u>
Step-by-step explanation:
subtract by the numbers. subtract it's to take away one number from to another from the difference between the numbers.
5-4/11
5-4=1
=1/11
You can also round up to the nearest hundredths is 0.10.
Hope this helps!
Thanks!
Have a great day!
×by 2 then find 10%and then times the 10% by 2 then add it on
Answer:
Eight times ten plus six times one plus two times one-tenth plus seven times one-thousandth.
Step-by-step explanation:
(8 x 10) = eight times ten
(6 x 1) = six times one
(2 x 0.1) = two times one-tenth
(7 x 0.001) = seven times one-thousandth
I am not always the best with the equations to words stuff, so please comment if I am wrong!
