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2 years ago

I need help plzzzzzzz

Mathematics

1 answer:

Gre4nikov [31]2 years ago

5 0

6) C, 7) B, 8) B, a spring scale is one tool that can be used to measure force. Explain that a spring scale measures force in units called newtons.

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Choose the inequality that represents the following graph.

inysia [295]

Answer:

Step-by-step explanation:

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3 years ago

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Expand and simplify (x-7)(x+3)

velikii [3]

X(x+3)-7(x+3)
x2+3x-7x-21
x^2-4x-21

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3 years ago

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Find a parametrization r ( t ) r(t) of the line through the origin whose projection on the x y - xy- plane is a line of slope 8

ankoles [38]

Answer:

please check the attached file for the answer

Step-by-step explanation:

the explanation is in the attached file

8 0

3 years ago

a meat pie contains chicken and turkey in the ratio 4:1. The pie contains 200g of Chicken. How much turkey is in the pie?

kogti [31]

Answer:

50 grams

Step-by-step explanation:

From the above question:

Chicken : Turkey

= 4:1

Sum Proportions = 4 + 1 = 5

We have to find the weight in grams of the entire pie

Let us represent the weight in grams of the entire pie = x.

The pie contains 200g of Chicken.

Hence:

4/5 × x = 200g

4x/5 = 200g

Cross Multiply

4x = 200g × 5

x = 200g × 5/4

x = 250g

The amount turkey that is in the pie is calculated as:

Total weight of pie - Amount of Chicken in the pie

= 250g - 200g

= 50 g

3 0

2 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

3 years ago