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allochka39001 [22]
2 years ago
11

What is an equation in point-slope form of the line that passes through the point (8, 5) and has slope −7?

Mathematics
1 answer:
hodyreva [135]2 years ago
3 0

Answer: D. y-5= -7(x-8)

Step-by-step explanation:

point slope form: y-y1=m(x-x1)

slope= -7

point: (8,5)

use the slope and point and plug it into point slope form equation.

y-5= -7(x-8),

The Answer would be D. y-5= -7(x-8)

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Whats 2x2+34x24+3x0+1x400x100x456x0
aivan3 [116]

Answer:

820

Step-by-step explanation:

If you use order of operations, you can find that 3x0 and 1x400x100x456x0 is just 0 so you just have to add 2x2 and 34x24. Which is 820

order of operations is

GEMDAS

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exponents

multiplication and division (these don't have to be in order)

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3 years ago
find an equation for the perpendicular bisector of the line segment whose endpoints are (-8,-5) and (-4,1)
lbvjy [14]

Answer:

y = -x - 8

Step-by-step explanation:

Midpoint of the line:

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so midpoint is (-6,-2)

Slope of the line: Slope m = (y2-y1)/(x2-x1)

m = (-1 - -5)/(-4 - -8) = (-1 + 5)/(-4 + 8) = 4/4 = 1

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of the perpendicular line is -1/1 is -1

y = mx + b

y = -x + b

Using (-6,-2)

-2 = -(-6) + b

-2 = 6 + b

b = -8

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6 0
2 years ago
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Answer:

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