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Paul [167]
2 years ago
12

How many solutions does the following system of equations have? {4x + 6y = 24 2x + 3y = 12

Mathematics
1 answer:
Mila [183]2 years ago
5 0

Answer:

Infinitely many solutions

Step-by-step explanation:

Note that 2(2x+3y=12) is 4x+6y=24, which is the first equation. Therefore, by canceling the equations out, you have 0=0, which means whatever one side equals, the other side ALWAYS equals that.

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2 years ago
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3 years ago
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Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

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3 years ago
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Answer:

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Step-by-step explanation:

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