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Paul [167]
2 years ago
12

How many solutions does the following system of equations have? {4x + 6y = 24 2x + 3y = 12

Mathematics
1 answer:
Mila [183]2 years ago
5 0

Answer:

Infinitely many solutions

Step-by-step explanation:

Note that 2(2x+3y=12) is 4x+6y=24, which is the first equation. Therefore, by canceling the equations out, you have 0=0, which means whatever one side equals, the other side ALWAYS equals that.

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A circle with a circumference of 6 has an arc with 20 central angle
marissa [1.9K]

Answer: 0.3 units

Step-by-step explanation: The ratio of the length of the arc to the circumference of the circle is proportional to the ratio of the central angle to the sum of angle in a circle.

7 0
3 years ago
Kaden, Keith, and Kipp compete in a series of daily 3-way races. For each race, the probability that Kaden wins is 1/6, the prob
BlackZzzverrR [31]

9514 1404 393

Answer:

  3/5

Step-by-step explanation:

Let a, b, c represent the probability of a win by Kaden, Keith, and Kipp, respectively.

  P(bc' | a') = P(a'bc')/P(a')

  P(bc' | a') = (1/2)/(1 -1/6) = (3/6)/(5/6) = 3/5

The probability is 3/5 that Keith beats Kipp when Kaden doesn't win.

4 0
3 years ago
the least square yard is 15 yards by 15 yards. how many feet of fencing will they need to buy to fence in all four sides
vekshin1
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6 0
3 years ago
12=15(z−51​)<br> What is Z
professor190 [17]

Answer:

51.8

Step-by-step explanation:

Multiply 15 by z and -51 which would equal (15z-765).

Add 765 to 12 and that equals 777

Divide 777 by 15 which would equal 51.8

4 0
3 years ago
You are given f(0) = 1 and g(0) = -2 and g(1) = 3. What is <br> g ∘ f ( 0 ) <br> equal to?
Sergeu [11.5K]

Answer:

  • <u><em>g∘f (0) = 1</em></u>

Explanation:

The <em>composition</em> of the <em>functions</em> f and g represented by g ∘ f ( 0 ) means that g is applied to f(0), i.e f(0) is the input to the function g.

Since f(0) = 1, you are going fo find g(1):

         \( g\circ f(x)=g(f(x)) \)\\\\\( g\circ f(0)=g(f(0)) \)\\\\\( g\circ f(0)=g(1) \)=3

4 0
3 years ago
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