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Misha Larkins [42]
3 years ago
9

Para la construcción de una cabaña en el campo don Samuel compró 7,943 clavos hasta el momento ha utilizado 473 ¿cuantos clavos

le queda?

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0

<u>Restando la cantidad utilizada de el total</u>, tiene-se que 7470 clavos le quedan.

----------------------

  • En total, para la construcción, Samuel compró 7,943 clavos.
  • De toda esta cantidad, 473 fueron utilizadas.
  • La cantidad de clavos que le quedan es la <u>subtracción da cantidad total por la utilizada</u>, o sea, 7943 restado de 473.

7943 - 473 = 7470

Le quedan 7470 clavos.

Un problema similar es dado en brainly.com/question/24554492

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Jane needs $20 to buy her radio. She has saved $15.
KonstantinChe [14]

Answer:

the answer is d

Step-by-step explanation:

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2 years ago
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This year, for the spring musical, the Drama Club sold 150% of the number of tickets they sold last year. Last year, the club so
babunello [35]

Answer:

C. 342

Step-by-step explanation:

This year, 150% of last year's tickets were sold.

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150% as a fraction is 150/100

To find the amount of tickets sold this year, we take the 150/100 and multiply it by 228:

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7 0
3 years ago
What is 0.29 of 200 rounded to the nearest hundred
jekas [21]

Answer:

100

Step-by-step explanation:

<u>Step 1:  Make an expression</u>

<u />200 * 0.29 = x

58 = x

<u>Step 2:  Round</u>

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Answer:  100

3 0
3 years ago
There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin
Ksju [112]

To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.

The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.

Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.

4 0
3 years ago
Which is another way to check the sum of 104+34+228+877?
Alex787 [66]
The answer is digit sum method.

Digit sum method is method used to check the sum of sum numbers. If the sum of all of the digits of numbers is equal to the sum of all of the digits of the total sum, then the arithmetic process was correct.

We need to check the sum of <span>104+34+228+877:
</span>104 + 34 + 228 + 877 = 1243

Let's first summarize the digits of individual numbers:
104 *** 1 + 0 + 4 = 5
34 *** 3 + 4 = 7
228 *** 2 + 2 + 8 = 12 *** 1 + 2 = 3
877 *** 8 + 7 + 7 = 22 *** 2 + 2 = 4

Now, let's sum these sums:
5 + 7 + 3 + 4 = 19 *** 1 + 9 = 10 *** 1 + 0 = <u><em>1</em></u>

Then, let's summarize the digits of the total sum:
1243 *** 1 + 2 + 4 + 3 = 10 *** 1 + 0 = <u><em>1</em></u>

Since the sums of the digits on the both sides of equation is 1, than the arithmetic process was correct and the sum of <span>104 + 34 + 228 + 877 is really 1243.</span>

7 0
3 years ago
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