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dem82 [27]
2 years ago
11

Which statement best describes f (x) = negative 2 startroot x minus 7 endroot 1? –6 is in the domain of f(x) but not in the rang

e of f(x). –6 is not in the domain of f(x) but is in the range of f(x). –6 is in the domain of f(x) and in the range of f(x). –6 is neither in the domain of f(x) nor in the range of f(x).
Mathematics
1 answer:
erastovalidia [21]2 years ago
6 0

Answer:

i have no idea

Step-by-step explanation:

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Which triangles can have two sides of the same lenghth
alisha [4.7K]

An isosceles triangle is a triangle with 2 congruent sides. The congruent sides are called legs and the third side is called the base. So if 2 sides of a triangle have the same length, then we say that the triangle is isosceles.

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3 years ago
Joshua's math textbook weighs 43.21 ounces. His social studies book weighs 38.99 ounces. What is the difference in weight betwee
Nuetrik [128]
43.21-38.99=4.22

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4 0
3 years ago
Can some explain steps​
Mashutka [201]

Answer:

r = 3.

Step-by-step explanation:

16 = 10 + √(3r + 27)

√(3r + 27) = 6

Square both sides:

3r + 27 = 36

3r = 36 - 27 = 9

r = 3.

Check the result:

Left side of the equation = 16

Right side = 10 + √(9 + 27)

                  = 10 + √36 = 16

5 0
2 years ago
Read 2 more answers
What does 49.39 round to.
Verizon [17]
If you want to round 49.39 to the nearest tenths place you will have to look at your tenths digit. The digit is 3, right? Look at the next number after 3. It is the number 9 for the hundredths place. If the number is bigger than 5 you round it. If it is smaller, you keep it the same. 9 is bigger than 5 so you make the 3 into a 4. Then, you're answer is 49.4 or 49.40 (Which are basically the same answer) It also works the same with the other digits. Simple, right? :)
4 0
3 years ago
Find the second derivative of 2x^3-3y^2=8​
Umnica [9.8K]

Answer:

\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

Step-by-step explanation:

<u>Find the first implicit derivative using implicit differentiation</u>

<u />2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}

<u>Use the substitution of dy/dx to find the second derivative (d²y/dx²)</u>

<u />\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

5 0
2 years ago
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