The solution to the problem is as follows:
<span>4 sqrt(16x^2 y^7)
Protip: sqrt(abc) = sqrt(a)sqrt(b)sqrt(c). Therefore,
4sqrt(16x^2y^7) = 4sqrt(16)sqrt(x^2)sqrt(y^7)
We can deal with sqrt(16); it is equal to 4.
4(4) sqrt(x^2)sqrt(y^7)
16sqrt(x^2)sqrt(y^7)
Next, it is a known fact that sqrt(z^2) is the same as |z|, or the absolute value of z. That means
sqrt(x^2) = |x|
16|x| sqrt(y^7)
Split y^7 as y^6 * y
16|x| sqrt(y^6 * y)
16|x| sqrt(y^6) sqrt(y)
16|x| sqrt([y^3]^2) sqrt(y)
16|x| |y^3| sqrt(y)
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2/236 is 18. You're welcome:)
Initial value: 1. rate of change: 3 over 5.
Answer:
savage love
Step-by-step explanation:
Answer:
x = 10/3
, y = 0
Step-by-step explanation:
Solve the following system:
{4.5 x - 2 y = 15
3 x - y = 10
In the first equation, look to solve for x:
{4.5 x - 2 y = 15
3 x - y = 10
4.5 x - 2 y = (9 x)/2 - 2 y:
(9 x)/2 - 2 y = 15
Add 2 y to both sides:
{(9 x)/2 = 2 y + 15
3 x - y = 10
Multiply both sides by 2/9:
{x = (4 y)/9 + 10/3
3 x - y = 10
Substitute x = (4 y)/9 + 10/3 into the second equation:
{x = (4 y)/9 + 10/3
3 ((4 y)/9 + 10/3) - y = 10
3 ((4 y)/9 + 10/3) - y = ((4 y)/3 + 10) - y = y/3 + 10:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
In the second equation, look to solve for y:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
Subtract 10 from both sides:
{x = (4 y)/9 + 10/3
y/3 = 0
Multiply both sides by 3:
{x = (4 y)/9 + 10/3
y = 0
Substitute y = 0 into the first equation:
Answer: {x = 10/3
, y = 0