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Wewaii [24]
3 years ago
15

Two complementary angles are in the ratio 7:8. What is the measure of the larger angle?

Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer

<h3>48°</h3>

Step-by-step explanation:

We know that sum of complementary angle adds to 90°

Let the angles be 7x and 8x

<u>First </u><u>of </u><u>all,</u><u> </u><u>finding </u><u>the </u><u>value </u><u>of </u><u>x</u>

\sf{7x + 8x = 90 °}

Collect like terms

⇒\sf{15x = 90 °}

Divide both sides of the equation by 15

⇒\sf{ \frac{15x}{15}  =  \frac{90}{15} }

Calculate

⇒\sf{x = 6 °}

The value of X is 6°

<u>Now,</u><u> </u><u>substituting </u><u>/</u><u> </u><u>Replacing</u><u> </u><u>the </u><u>value </u><u>of </u><u>x</u>

⇒\sf{7x = 7 \times  6 = 42}

⇒\sf{8x = 8 \times 6 = 48}

The measure of larger angle is 48°

Hope I helped!

Best regards!!

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3 years ago
What is being constructed based on the markings in the following diagram?
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Answer:

  perpendicular line through a point on a line

Step-by-step explanation:

The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.

The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)

So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.

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2 years ago
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The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia
sveta [45]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Technician __Shutdown

Taylor, T___4

Rousche, R _ 3

Hurley, H__ 3

Huang, Hu___2

Gupta, ___ 5

The Numbe of samples of 2 possible from the 5 technicians :

We use combination :

nCr = n! ÷ (n-r)!r!

5C2 = 5!(3!)2!

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POSSIBLE COMBINATIONS :

TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG

Sample means :

TR = (4+3)/2 = 3.5

TH = (4+3)/2 = 3.5

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Population mean :

(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4

Population Mean and mean of sample means are the same.

This distribution should be approximately normal.

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