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levacccp [35]
3 years ago
8

Problem How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

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Answer:

A. The value of x is 5

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Step-by-step explanation:

For part A., We can determine x by setting these equations to equal each other (as we know that all sides of a square are equal)! See below for how to:

4x = 2x +10\\2x = 10\\x=5

For part B. sub x for 5 to get the side length of one side...

4(5) = 20\\2(5) +10=20

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4 0
3 years ago
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Step-by-step explanation:

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3 years ago
A boy weighing blank kilograms is riding a skateboard. He’s moving at 2 meters/second and has 40 joules of kinetic energy. He do
Ira Lisetskai [31]

Answer:

His kinetic energy at the faster speed is 160 J

Step-by-step explanation:

Here in this question, we are interested in calculating the kinetic energy at the faster speed.

Firstly, we need to know the mass of the boy’s body. We can do this by using the kinetic energy formula;

Mathematically;

K.E = 1/2 * m * v^2

From the question;

K.E = 40 Joules

m = ?

v = speed = 2 m/s

Now, plugging these values into the kinetic energy equation, we have;

40 = 1/2 * m * 2^2

40 = 1/2 * m * 4

40 = 4m/2

4m = 40 * 2

4m = 80

m = 80/4

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Now that we know the mass of the boy’s body, we can proceed to calculate the new K.E

Let’s follow the third statement in the question;

We were told that he doubles his speed upon sighting his friend.

Recall, he was traveling at a speed of 2 m/s.

Now doubling this means the new speed will

be 2 * 2 = 4 m/s

Now, we want to calculate the kinetic energy value at this new speed.

Mathematically, we use the same formula for kinetic energy.

K.E = 1/2 * m * v^2

We know that m is the mass that we calculated as 20kg and our v here is 4 m/s

Plugging these values, we have;

K.E = 1/2 * 20 * 4^2

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K.E = 160 J

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