All categories

2 years ago

8. Mario walks 7 blocks from his home to

Mathematics

2 answers:

Vika [28.1K]2 years ago

6 0

I believe the answer is 2. i hope this helps

lozanna [386]2 years ago

5 0

Answer:

2 Blocks from his house

Step-by-step explanation:

Mario walks <u>7 blocks</u> from his home

0+7

to a restaurant. He then walks back toward home for <u>five blocks</u>, where he stops at a bookstore. How many blocks is Mario from his home?

0+7= 7

7-5= 2 Blocks

You might be interested in

How do you read a line pointu

snow_tiger [21]

By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think

5 0

2 years ago

Find the exact value of tan A in simplest radical form.

spin [16.1K]

Answer:

$tan(A) = \frac{2\sqrt{15}}{11}$

Step-by-step explanation:

Given:

Right ∆ABC

AB = 61

BC = 60

AC = 11

Required:

Value of tan A in radical form

SOLUTION:

$tan(A) = \frac{opposite}{adjacent}$

Opposite = 60

Adjacent = 11

$tan(A) = \frac{60}{11}$

$tan(A) = \frac{\sqrt{4*15}}{11}$

$tan(A) = \frac{2\sqrt{15}}{11}$

6 0

2 years ago

Choose the linear inequality that describes the graph. The gray area represents the shaded region.

jek_recluse [69]

Answer:

2x + 3y ≥ 5

Step-by-step explanation:

See the graph attached.

The bold straight line passes through the points (1,1) and (4,-1).

Therefore, the equation of the straight line will be

$\frac{y + 1}{- 1 - 1} = \frac{x - 4}{4 - 1}$

⇒ 3(y + 1) = - 2(x - 4)

⇒ 3y + 3 = - 2x + 8

⇒ 2x + 3y = 5 ............. (1)

Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).

So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5

Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)

6 0

3 years ago

Prove that 1/sin^2A -1/tan^2A= 1

Vika [28.1K]

Answer:

Step-by-step explanation:

$LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS$

Hint: 1 - Cos² A = Sin² A

4 0

2 years ago

Find the area and perimeter

spin [16.1K]

Answer:

area (A) =(9x+108)unit^2

perimeter (P) =(2x+42) units

Step-by-step explanation:

area(A) =length(l) × breadth(b)

perimeter(P) =2(l+ b) {which is sum of all sides}

so, l = 7+x+5 = (x+12) units and b = 9 units

now, A=(x+12) × 9 units^2

=(9×x + 12×9 ) units^2

Therefore,

A =(9x+108)unit^2

next, P=2{(x+12)+9}

=2(x+21)

Hence,

P=(2x+42) units

3 0

3 years ago