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Afina-wow [57]
2 years ago
5

Where is the line of symmetry of this parabola? Write its equation.

Mathematics
1 answer:
lisov135 [29]2 years ago
7 0
Line of symmetry is at x= -1.25.
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solong [7]

Answer:

multiply 77 by 10 which is 770 then you multiply it by 5 which is half of 10 so 385 then add them together and you get 1155

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A recipe uses 1 1/2 teaspoons of baking powder to make 8 blueberry muffins. How much baking powder is needed to make 36 muffins
sladkih [1.3K]
6.75 teaspoons 
So it takes 0.1875 teaspoon of baking powder to make one muffin. Then you just multiply 0.1875 by 36 and you get 6.75.   :)

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Rewrite the expression so that the GCF is factored completely: 2x^3y+18xy-10x^2y-90y
Agata [3.3K]

2x^3y+18xy-10x^2y-90y

= 2xy(x^2 + 9)- 10y(x^2 + 9)

= (x^2 + 9)(2xy - 10y)

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6 0
3 years ago
Read 2 more answers
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
Someone please help me with this question please
Eddi Din [679]

Answer: False

Step-by-step explanation:

6 0
3 years ago
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