Where is the line of symmetry of this parabola? Write its equation.
1 answer:
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We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where
(h,k) is the vertex of the parabola
if a> 0 then
the parabola opens upwards
if a< 0
then the parabola open downwards
in this problem we have
f(x)=−5(x+7)²<span>+6
</span>a=-5
so
a< 0 -------> the parabola open downwards
the vertex is the point (-7,6) is a maximum
the answer is the option
<span>a = -5, opens down</span>
see the attached figure
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where
(h,k) is the vertex of the parabola
if a> 0 then
the parabola opens upwards
if a< 0
then the parabola open downwards
in this problem we have
f(x)=−5(x+7)²<span>+6
</span>a=-5
so
a< 0 -------> the parabola open downwards
the vertex is the point (-7,6) is a maximum
the answer is the option
<span>a = -5, opens down</span>
see the attached figure
Hello :D
Answer:
The answer should have a negative sign.
Step-by-step explanation:
First, you do is divide by 17 from both sides of an equation.
Then, you simplify and solve to find the answer.
, which is our answer.
I hope this helps you!
Have a great day! :D