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ale4655 [162]
3 years ago
12

PLZ PLZ PLZ PLZ PLZ HELP, I HAVE TWO MORE QUESTIONS IF YOU WANT MORE POINTS

Mathematics
1 answer:
12345 [234]3 years ago
8 0
B/5 > 30

we’re going to simplify by multiplying by 5 on both sides.

b > 150 should be the answer!
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Fill in the blank with a number to make the expression a perfect square.
Mariana [72]

Answer: 36

Step-by-step explanation: We can actually mental math this question, since perfect squares are squares obviously, 6 squared is <u>36</u>. Hope this helps, 15402256!

3 0
3 years ago
Solve and graph the absolute value inequality: |2x + 4| &gt; 8​
neonofarm [45]

Answer:

C

Step-by-step explanation:

To get rid of the absolute value bars you have to get two different equations which would be 2x+4>-8 AND 2x+4>8. Pay attention to the signs, if there is greater than or equal to then it would have a line underneath the sign, which neither of the equations should have since you haven't moved a negative. solve normally and you'll get -6 blank circle and 2 blank circle.

4 0
3 years ago
PLEASE HURRY!!!! TIMED!!!! WILL GIVE BRAINLIEST!!!!
sweet-ann [11.9K]

Answer:

\sqrt{28}

Step-by-step explanation:

You don't need to memorize all of the square roots.  Looking at each square root, find a number close to it that you know -- The square root of five is close to the square root of four, which is 2. The square root of 28 is close to the square root of 25, which is 5.  28 is a slightly bigger than 25, so the square root will be slightly greater than 5.

3 0
3 years ago
Can somebody help me with this problem!? i need help ahh
slamgirl [31]

for these kinds of problems the outside angle always equals the opposite 2. meaning angle x=64+70 which is 134 degrees. you can double check this because all triangles equal 180 degrees. meaning that the last angle in the triangle is 46. 46+70+64=180.

so your answer is 134.

hope this helps :)

6 0
3 years ago
Read 2 more answers
Limx→+∞​ (x-(lnx)^2) =?​
expeople1 [14]

\lim_{x\to\infty}(x-\ln(x)^2) \\\lim_{x\to\infty}(x-2\ln(x)) \\\lim_{x\to\infty}\Big(x\Big(1-\dfrac{2\ln(x)}{x}\Big)\Big) \\\lim_{x\to\infty}x\cdot\lim_{x\to\infty}\Big(1-\dfrac{2\ln(x)}{x}\Big) \\\infty\cdot\Big(\lim_{x\to\infty}(1)-\lim_{x\to\infty}\Big(\dfrac{2\ln(x)}{x}\Big)\Big) \\\infty\cdot(1-2\lim_{x\to\infty}(1/x)) \\\infty\cdot(1-0) \\\infty\cdot1=\boxed{\infty}

Hope this helps.

3 0
3 years ago
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